Question

Match the compounds given in column I with oxidation states of carbon given in column II and mark the apropriate choice.

	Column I		Column II
(A)	$C_6{H}_{12}{O}_6$	(i)	+3
(B)	$CHC{l}_3$	(ii)	-3
(C)	$C{H}_{3}C{H}_3$	(iii)	+2
(D)	$(COOH{)}_2$	(iv)	0

• A. ( A )$\to$( iv ), ( B )$\to$ ( iii ), ( C ) $\to$ ( ii ) , ( D ) $\to$ (i)
  
• B. ( A )$\to$ ( i ) , ( B )$\to$ ( ii ) , ( C ) $\to$ ( iii ) , ( D ) $\to$ ( iv )
• C. ( A ) $\to$ ( ii ), ( B ) $\to$ ( iii ), ( C ) $\to$ ( iv ), ( D ) $\to$ ( i )
• D. ( A ) $\to$ ( iii ), ( B ) $\to$ ( ii ) , ( C ) $\to$ ( i ) , ( D ) $\to$ ( iv )

Answer 1

The correct option is A ( A )$\to$( iv ), ( B )$\to$ ( iii ), ( C ) $\to$ ( ii ) , ( D ) $\to$ (i)

Let the oxidation number of carbon be $x$.

Oxidation state of $H=+1$, $Cl=-1$ and of $O=-2$.

(A) $C_6{H}_{12}{O}_6$:

$6x+12\times 1+6\times (-2)=0$

$6x+12-12=0$

or $x=0$ = (iv)

(B) $CHC{l}_3$:

$x+1+3\times (-1)=0$

$x+1-3=0$

or $x=+2$=(iii)

(C) $C{H}_{3}C{H}_3$:

$x+3\times 1+x+3\times 1=0$

$2x+6=0$

or $x=-3$=(ii)

(D) $(COOH{)}_2$:

$2\times [x+(-2)+(-2)+1]=0$

$x-3=0$

or $x=+3$=(i)

A-(iv), B-(iii), C-(ii), D(i)