Question

Match the compounds given in Column I with the hybridization and shape given in Column II and mark the correct option.

	Column I		Column I
a	$Xe{F}_6$	(i)	$S{p}^3{d}^3$ - distorted octahedral
b	$Xe{O}_3$	(ii)	$S{p}^3{d}^3$ - square planar
c	$XeO{F}_4$	(iii)	$S{p}^3{d}^3$ - pyramidal
d	$Xe{F}_4$	(iv)	$S{p}^3{d}^3$ - square pyramidal

• A. $a\to \left(iv\right)b\to \left(i\right)c\to \left(ii\right)d\to \left(iii\right)$
• B. $a\to \left(iv\right)b\to \left(iii\right)c\to \left(i\right)d\to \left(ii\right)$
• C. $a\to \left(i\right)b\to \left(iii\right)c\to \left(iv\right)d\to \left(ii\right)$
• D. $a\to \left(i\right)b\to \left(ii\right)c\to \left(iv\right)d\to \left(iii\right)$

Answer 1

The correct option is C $a\to \left(i\right)b\to \left(iii\right)c\to \left(iv\right)d\to \left(ii\right)$

Steric number to find hybridization

Hybridization can be calculated by finding the steric number for a given molecule.
Steric number
= number of sigma bonds + number of lone pairs
Based on steric number, hybridization of molecules can be:

Steric Number	Hybridization
2	sp
3	$s{p}^2$
4	$s{p}^3$
5	$s{p}^{3}d$
6	$s{p}^3{d}^2$
7	$s{p}^3{d}^3$

Part (a)

$Xe{F}_6$
Structure:


Number of sigma bonds = 6
Number of lone pairs = 1

So, steric number = number of sigma bonds + number of lone pairs
= 6 + 1
= 7

For steric number 7, hybridization is $s{p}^3{d}^3$ and shape is distorted octahedral.

$a\to i$

Part (b)
$Xe{O}_3$
Structure:



Number of sigma bonds = 3
Number of lone pairs = 1

So, steric number = 3 + 1 = 4

For steric number 4, hybridization is $s{p}^3$ and shape is pyramidal as there is one lone pair.

$b\to iii$

Part (c)
$XeO{F}_4$
Structure:



Number of sigma bonds = 5
Number of lone pairs = 1

So, steric number = 5 + 1 = 6

For steric number 6, hybridization is $s{p}^3{d}^2$ and shape is square pyramidal.

$c\to iv$

Part (d)
$Xe{F}_4$
Structure:



Number of sigma bonds = 4
Number of lone pairs = 2

So, steric number = 4 + 2 = 6

For steric number 6, hybridization is $s{p}^3{d}^2$ and shape is square planar.

$d\to ii$

Final answer: $a\to \left(i\right)b\to \left(iii\right)c\to \left(iv\right)d\to \left(ii\right)$
Hence, option (A) is correct.