Question

Match the compounds (in List I) with the type of hybridsation on the central atom/ion (in List II).

Answer 1

$BC{l}_3$: 3 bond pair = $s{p}^2$;

$N{H}_3$: 3 bond pair + 1 lone pair =$s{p}^3$;

$\left[Cu\right(N{H}_3{)}_4{]}^{2+}$: square planar = $ds{p}^2$;

$\left[Fe\right(H_{2}O{)}_6{]}^{2+}$: octahedral = $s{p}^3{d}^2$