Match the correct combination:

Column I Column II

A) $B_{2} H_{6}$ P) Lewis acid
B) $B F_{3}$ Q) Tetrahedral
C) $A l C l_{3}$ R) $s p^{3}$ hybridisation
D) $B H_{4}^{-}$ S) Planar molecule

A \to P, Q, R; B \to P, S; C \to P, S; D \to Q, R

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A \to P, S; B \to P, S; C \to Q, R; D \to P, S

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A \to Q, R; B \to P, S; C \to R, S; D \to P, S

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A \to P, S; B \to P, S; C \to Q, R; D \to R, S

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Solution

The correct option is A $A \to P, Q, R; B \to P, S; C \to P, S; D \to Q, R$

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\begin{matrix} Column -I & Column -II (a) N H_{4} C l & (P) Hydrogen bond (b) C u S O_{4} .5 H_{2} O & (Q) Co-ordinate bond (c) H N C & (R) Ionic bond (d) L i q u i d H_{2} O_{2} & (S) Covalent bond \end{matrix}

\begin{matrix} Column -I & Column -II (a) N H_{4} C l & (P) Hydrogen bond (b) C u S O_{4} .5 H_{2} O & (Q) Coordinate bond (c) H N C & (R) Ionic bond (d) L i q u i d H_{2} O_{2} & (S) Covalent bond \end{matrix}

Column I

Column II

\begin{matrix} C o l u m n I & C o l u m n I I (T y p e o f △ A B C) a. cot \frac{A}{2} = \frac{b + c}{a} & p. always right angled b. a tan A + b tan B = (a + b) tan \frac{A + B}{2} & q. always isosceles c. a cos A = b cos B & r. may be right angled d. cos A = \frac{sin B}{2 sin C} & s. may be right angled isosceles \end{matrix}

s p^{3}

B F_{3}

s p^{2}

\begin{matrix} C o l u m n - I (I d e a l G a s) & Column - II (Related equation) (A) Reversible isothermal process & (P) W = 2.303 n R T l o g (P_{2} / P_{1}) (B) Reversible adiabatic process & (Q) W = n C_{v, m} (T_{2} - T_{1}) (C) Irreversible adiabatic process & (R) P V = n R T (D) Irreversible isothermal process & (S) W = - \int_{v_{i}}^{v_{f}} P_{e x t .} d V \end{matrix}

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