Match the correct pairs of isomers with their examples.
A)Ionisation (a) $P t (N H_{3})_{2} C l_{2}] [P t (N H_{3})_{4}]$
$[P t C l_{4}]$
B) Linkage (b) $[C r (N H_{3})_{6}] [C o (C N)_{6}]$ & $[C o (N H_{3})_{6} [C r (C N)_{6}]$
C)Coordination (c) $[C o (N H_{3})_{5} (N O_{2})] C l_{2}$ & $[C o (N H_{3})_{5} (O N O)] C l_{2}$
D)Polymerisation (d) $[C o (S O_{4}) (N H_{3})_{5}] B r$ & $[C o (B r (N H_{3})_{5}] S O_{4}$

A -> a, B -> b, C -> c, D -> d

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A -> b, B -> a, C -> d, D -> c

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A -> d, B -> c, C -> b, D -> a

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A -> d, B -> b, C -> c, D -> a

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Solution

The correct option is D A -> d, B -> c, C -> b, D -> a
$P o l y m e r i z a t i o n I s o m e r i s m$ : This is not true isomerism because it occurs between compounds having the same empirical formula, but different molecular weights.
For example, $[P t (N H_{3})_{2} C I_{2}], [P t (N H_{3})_{4}] [P t C I_{4}], [P t (N H_{3})_{4}] [P t (N H_{3}) C I_{3}]_{2}$ .
$I n o n i z a t i o n I s o m e r i s m$ : This type of isomerism is due to the exchange of groups between the complex ion and the ions outside it. $[C o (N H_{3})_{5} B r] S O_{4}$ is red-violet. An aqueous solution gives a white precipitate of $B a S O_{4}$ with $B a C I_{2}$ solution, thus confirming the presence of free $S O_{4}^{2 -}$ ions. In contrast $[C o (N H_{3})_{5} S O_{4}] B r$ is red. A solution of this complex does not give a positive sulphate test with $B a C I_{2}$ .It does give a cream-coloured precipitate of $A g B r$ with $A g N O_{3}$ , thus confirming the presence of free $B r^{-}$ ions.
$L i n k a g e I s o m e r i s m$ : Certain ligands contain more than one atom which could donate an electron pair. In the $N O_{2}^{-}$ group in the complex ion. In the $N O_{2}^{-}$ ion, either $N$ or $O$ atoms could act as the electrons pair donor. Thus there is the possibility of isomerism. Two different complexes $[C o (N H_{3})_{5} N O)_{2}] C l_{2}$ and $[C o (N H_{3})_{5} (O N O)] C l_{2}$ have been prepared, each containing the $N O_{2}^{-}$ group in the complex ion.
$C o o r d i n a t i o n I s o m e r i s m$ : If the complex is a salt having both cation and anion as complex ions then the ligands can exchange position between the cation and the anion. This will result in the formation of coordinates isomers. For example
$[C o (e n)_{3}] [C r (C_{2} O_{4})_{3}]$ and $[C o (e n)_{2} (C_{2} O_{4})] [C r (e n) (C_{2} O_{4})_{2}]$
$[C r (e n)_{2} (C_{2} O_{4})] [C o (e n) (C_{2} O_{4})_{2}]$ and $[C r (e n)_{3}] [C o (C_{2} O_{4})_{3}]$

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