The correct option is
B A→q,
r;
B→q,
r;
C→q,
s;
D→p,
sConvex mirror always produces virtual and diminished image of a real object.
Thus,
m=+ve and
m<1.
Real images are always inverted, hence
m=−ve Virtual images are always erect, hence
m=+ve If images are enlarged then
m>1 and if diminished then
m<1.
For a concave mirror, a virtual and enlarged image will be formed for position of the object between Pole
(P) and focus
(F) and in all other cases a real and inverted image is formed.
Now,
(A) m=−2, indicates an enlarged real image formed by a concave mirror.
(B) m=−12, indicates a diminished real image produced by concave mirror.
(C) m=+2, indicates a virtual and enlarge image produced by concave mirror.
(D) m=+12, indicates a diminished virtual image produced by a convex mirror.
∴A→q,
r;
B→q,
r;
C→q,
s;
D→p,
s