Question

Match the description of image in column I with optical system in column II. Column-I Column-II


Which of the following option has the correct combination considering column-I and column-II.

• A. $A\to P,Q,R$
• B. $A\to S,T$
• C. $C\to R$
• D. $D\to T$

Answer 1

The correct option is C $C\to R$

For option $(a,b)$ :-
For concave mirror
$u=-15\text{cm},f=-10\text{cm}$
$\because \frac{1}{f}=\frac{1}{v}+\frac{1}{u}$
$\Rightarrow \frac{1}{v}=\frac{1}{f}-\frac{1}{u}$
$\Rightarrow \frac{1}{v}=\frac{1}{-10}+\frac{1}{15}$
$\Rightarrow \frac{1}{v}=\frac{-3+2}{30}\Rightarrow v=-30\text{cm}$
$\Rightarrow$ Image will be real and inverted.
$m=-\frac{v}{u}=-\frac{(-30)}{-\left(15\right)}=-2$
$\Rightarrow$ Image will be magnified.
As we know that the plane mirror always form virtual, erect and same size of image as that of the object is placed in front of it.
Option $a,b$ are incorrect

For option $\left(c\right)$ :-
$u=-15\text{cm},f=-10\text{cm}$
$\because \frac{1}{f}=\frac{1}{v}+\frac{1}{u}$
$\Rightarrow \frac{1}{v}=\frac{1}{f}-\frac{1}{u}$
$\Rightarrow \frac{1}{v}=\frac{1}{-10}+\frac{1}{15}$
$\Rightarrow \frac{1}{v}=\frac{-3+2}{30}\Rightarrow v=-30\text{cm}$
$\Rightarrow$ Image will be real inverted
$m=-\frac{v}{u}=-\frac{(-30)}{-\left(15\right)}=-2$
$\Rightarrow$ Image will be magnified.
Option $c$ is correct.

For option (d) :-
Plane mirror forms virtual, erect and same size image as the object is placed in front of it.
Option $d$ is incorrect