Question

Match the elements of given atomic number with their properties.

	Column $I$		Column $II$
$P$	$11$	$1$	IE is maximum among the given elements
$Q$	$19$	$2$	Alkali metal
$R$	$37$	$3$	Largest size among the given elements
$S$	$55$	$4$	Position next to $Kr$

• A. $P-1:Q-1,2:R-1,2:S-3,4$
• B. $P-2,3:Q-1,2:R-2,4:S-2,3$
• C. $P-1,2:Q-2,4:R-2,4:S-2,3$
• D. $P-1,2:Q-2,:R-2,4:S-2,3$

Answer 1

The correct option is D $P-1,2:Q-2,:R-2,4:S-2,3$

Atomic number of $Na$ is $11$ and atomic number of $K$ is $19$. Both are alkali metals present in group $I$.
$Na$, atomic number $11$, has the highest ionization energy amoung the given.It is due to the lowest ionic radius of $Na$ among the four. As we move down the group, ionization energy decreases as size increases.
Element with atomic number $55$ has the largest atomic size. As we move down the group atomic size increases.
Element with atomic number $55$ is an alkali metal and has the largest size in given elements.
Element with atomic number $37$ is next to Krypton as its atomic number is $36$.