CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Match the elements of list I with list II.

Open in App
Solution

List II is same as List I
Thus x2+y2+z22x4y+2Z3=0

Hence the centre of the given sphere is (1,2,1)
Similarily x2+y2z2+2x+4y+2Z+3=0

the 2x23y2+z2+4x+6y4Z2=0
hence 2x22y2+z24x+8y2Z5=0

2x23y2+z2+4x+6y4Z2=0
Finally 2x23y2+z2+4x+6y4Z2=0
We get centre of the given sphere is (1,1,2)








flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Properties of Set Operation
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon