Question

Match the elements with the number of electrons present in their L-shell.
$$\begin{array}{cc}\text{Elements}& \text{Electrons in L-shell}\\ \text{(a) Hydrogen}& \text{(i) 8}\\ \text{(b) Nitrogen}& \text{(ii) 0}\\ \text{(c) Lithium}& \text{(iii) 1}\\ \text{(d) Neon}& \text{(iv) 5}\end{array}$$

• A. $\text{(a) - (i)}$
  $\text{(b) - (iv)}$
  $\text{(c) - (ii)}$
  $\text{(d) - (iii)}$
• B. $\text{(a) - (ii)}$
  $\text{(b) - (iv)}$
  $\text{(c) - (iii)}$
  $\text{(d) - (i)}$
• C. $\text{(a) - (iii)}$
  $\text{(b) - (i)}$
  $\text{(c) - (ii)}$
  $\text{(d) - (iv)}$
• D. $\text{(a) - (iv)}$
  $\text{(b) - (iii)}$
  $\text{(c) - (ii)}$
  $\text{(d) - (i)}$

Answer 1

The correct option is B $\text{(a) - (ii)}$

$\text{(b) - (iv)}$
$\text{(c) - (iii)}$
$\text{(d) - (i)}$
Atomic number of hydrogen is 1 and its single electron is in the K-shell. Thus, there are no electrons in the L-shell of hydrogen atom.

The elements with their electronic configuration and number of electron(s) present in their L-shell are given below:

$$\begin{array}{ccc}\text{Elements}& \text{Electronic configuration}& \text{Electrons in L-shell}\\ \text{Hydrogen}& 1& \text{0}\\ \text{Nitrogen}& 2,5& \text{5}\\ \text{Lithium}& 2,1& \text{1}\\ \text{Neon}& 2,8& \text{8}\end{array}$$