Question

Match the entries of List-A with List-B.

Answer 1

(a) $(x-3{)}^2>0$ for all real values of $x$ except $x=3$
(b) $(x+1)(x-4)<0\Rightarrow x$ lies between $-1$ and $4$
(c) $△=-ive$ and hence its sign is same as of the first term $\forall$ real values of $x$.
(d) $-3x^2+4x-5>0\Rightarrow 3x^2-4x+5=0$
Arguing as in (c), $△=ive$ and hence its sign is same as of $3$ i.e. $+ive$. Hence there will be no real values of $x$ for which this will hold.