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Standard X

Mathematics

Intercept Form of a Straight Line

Match the equ...

Question

Match the equations A, B, C and D with the lines $L_{1}, L_{2}, L_{3} a n d L_{4}$ , whose graphs are roughly drawn in the given diagram.

A $\equiv$ y = 2x; B $\equiv$ y - 2x + 2 = 0;

C $\equiv$ 3x + 2y = 6; D $\equiv$ y = 2

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Solution

Putting x = 0 and y = 0 in the equation y = 2x, we have:

LHS = 0 and RHS = 0

Thus, the line y = 2x passes through the origin.

Hence, A = L₃

Putting x = 0 in y - 2x + 2 = 0, we get, y = -2

Putting y = 0 in y - 2x + 2 = 0, we get, x = 1

So, x-intercept = 1 and y-intercept = -2

So, x-intercept is positive and y-intercept is negative.

Hence, B = L₄

Putting x = 0 in 3x + 2y = 6, we get, y = 3

Putting y = 0 in 3x + 2y = 6, we get, x = 2

So, both x-intercept and y-intercept are positive.

Hence, C = L₂

The slope of the line y = 2 is 0.

So, the line y = 2 is parallel to x-axis.

Hence, D = L₁

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Similar questions

Match the equations A, B, C, D with the lines L₁, L₂, L₃, L₄, L₅ whose graphs are roughly drawn in the adjoining figure.

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Match the equations A, B, C and D with the lines L1,L2,L3 and L4, whose graphs are roughly drawn in the given diagram. A ≡ y = 2x; B ≡ y - 2x + 2 = 0; C ≡ 3x + 2y = 6; D ≡ y = 2

Match the equations A, B, C and D with the lines $L_{1}, L_{2}, L_{3} a n d L_{4}$ , whose graphs are roughly drawn in the given diagram.

A $\equiv$ y = 2x; B $\equiv$ y - 2x + 2 = 0;

C $\equiv$ 3x + 2y = 6; D $\equiv$ y = 2