Question

Match the equations with their solutions

Answer 1

A) $14\frac{x-1}{10}=\frac{x+5}{6}-3$

$(140-x+1)6=(x+5-8)10$

$864-6x=10x-130$

$16x=976$

$x=61$

B) $(x-5{)}^2-(x+3{)}^2=48$

$(x-5+x+3)(x-5-x-3)=48$

$\because a^2-b^2=(a+b)(a-b))$

$(2x-2)(-8)=48$

$x-1=-3$

$x=-2$

C) $6(x-4)=4(x-3)-(3x-8)$

$6x-24=4x-12-3x+8$

$5x=20$

$\therefore x=4$

D) $(2x-1)(2x+3)=(2x-7)(2x+7)$

$4x^2+6x-2x-3=4x^2-49$

$4x=-46$

$x=\frac{-23}{2}=-11\frac{1}{2}$