Question

Match the equivalent weight given in list I with the reactions involved in list II.

Answer 1

When $Fe(SCN{)}_2$ oxidises into $F{e}^{3+},S{O}_4^{2-},C{O}_3^{2-}$ and $N{O}_3^{-}$, the relationship between equivalent weight and molecular weight is,
$Eq.wt.=\frac{Molecularweight}{33}$.
Wnen $Cr{I}_3$ oxidises into $C{r}_2{O}_7^{2-}$ and $I{O}_4^{-}$, the relationship between equivalent weight and molecular weight is,
$Eq.wt.=\frac{Molecularweight}{27}$.
When $A{s}_2{S}_3$ oxidises into $As{O}_3^{-}$ and $S{O}_4^{2-}$ the relationship between equivalent weight and molecular weight is,
$Eq.wt.=\frac{Molecularweight}{28}$.
When $N{H}_{4}SCN$ oxidizes into $S{O}_4^{2-},C{O}_3^{2-}$ and $N{O}_3^{-}$, the relationship between equivalent weight and molecular weight is,
$Eq.wt.=\frac{Molecularweight}{24}$.