The correct option is
D (i)
→ (b), (ii)
→ (c), (iii)
→ (a), (iv)
→ (d)
In fig (i),
△ADB and
△ADCIt is given that, AB=AC, ∠ADB=∠ADC=90o and AD=AD
∴ So, By RHS criteria $△ADB≅△ADC
In fig (ii), △BAD and △DCB
It is given that, BA=DC,AD=CB and BD=DB
∴ By SSS criteria △BAD≅△DCB
In fig (iii), △ABC and △CDA
AB∥CD and BC∥DA
∠BAC=∠DCA and ∠BCA=∠DAC [Alternate angles between parallel lines]
AC=CA [Common side]
∴ △ABC≅△CDA, by ASA criteria.
In fig (iv), △ABE and △DCE
It is given that, AB=DC,∠A=∠D and AE=DE
∴ △ABE≅△DCE, by SAS criteria.
∴ Correct answer is option C.