Match the following
1. PCl3 (i). 2 lone pairs (I) 5 Ligands
2. ClF3 (ii). 3 lone pair (II) 3 Ligands
3. XeF6 (iii). 0 lone pair (III) 6 Ligands
4. SbCl5 (iv). 1 lone pairs (IV) 4 Ligands
1 - (iv), (II); 2 - (i), (II); 3 - (iv), (III), 4 - (iii), (I)
Lets calculate the ep values first:
ep = (V+L+A−C)2
(1) PCl3⇒(5+3)2=4⇒ 1 lone pair
(2) ClF3⇒(7+3)2=5⇒ 2 lone pair
(3) XeF6⇒(8+6)2=7⇒ 1 lone pair
(4) SbCl5⇒(5+5)2=5⇒ 0 lone pairs