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Question

Match the following

1. PCl3 (i). 2 lone pairs (I) 5 Ligands

2. ClF3 (ii). 3 lone pair (II) 3 Ligands

3. XeF6 (iii). 0 lone pair (III) 6 Ligands

4. SbCl5 (iv). 1 lone pairs (IV) 4 Ligands


A

1 - (ii), (III); 2 - (ii), (II); 3 - (i), (I), 4 - (i), (I)

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B

1 - (iv), (II); 2 - (i), (II); 3 - (iv), (III), 4 - (iii), (I)

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C

1 - (ii), (II); 2 - (ii), (III); 3 - (ii), (II), 4 - (i), (I)

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D

1 - (iii), (II); 2 - (i), (III); 3 - (i), (II), 4 - (i), (II)

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Solution

The correct option is B

1 - (iv), (II); 2 - (i), (II); 3 - (iv), (III), 4 - (iii), (I)


Lets calculate the ep values first:

ep = (V+L+AC)2

(1) PCl3(5+3)2=4 1 lone pair

(2) ClF3(7+3)2=5 2 lone pair

(3) XeF6(8+6)2=7 1 lone pair

(4) SbCl5(5+5)2=5 0 lone pairs


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