Let's use the product of sum property here to simplify the sums given.
A.8×(20+5+6)
Using the property of products of sum:
⇒8×(20+5+6)=8×20+8×5+8×6
⇒8×(20+5+6)=160+40+48
⇒8×(20+5+6)=248
B.(6+8+9)×13
Using the commutative property of multiplication:
⇒(6+8+9)×13=13×(6+8+9)
And, using the property of sum of products:
⇒13×(6+8+9)=13×6+13×8+13×9
⇒13×(6+8+9)=78+104+117
⇒13×(6+8+9)=299
C.9×398
Here, we can either find the product using the long multiplication method or by using product of sums.
For product of sums we can write
398=300+90+8
And, hence the product becomes
9×(300+90+8)
And, using the product of sums:
⇒9×(300+90+8)=9×300+9×90+9×8
⇒9×300+9×90+9×8=2700+810+72
⇒9×300+9×90+9×8=3582
⇒9×398=3582
D.
7×1021
Let's use the product of sums method here.
For that, we can write
1021=1000+20+1
So, the product becomes:
7×(1000+20+1)
Now, using the product of sums method:
⇒7×(1000+20+1)=7×1000+7×20+7×1
⇒7×1000+7×20+7×1=7000+140+7
⇒7×1000+7×20+7×1=7147
⇒7×1021=7147