Question

Match the following:

A) $1.008$ g of $H_2$	1) $0.1$ gram atom
B) $245$ g of $KCl{O}_3$	2) $22.4$ L at S.T.P
C) $71$ g of $C{l}_2$	3) $12.046\times {10}^{23}$
D) $10.8$ grams of Ag	4) $3.0115\times {10}^{23}$

• A. A - 4, B - 3, C - 2, D - 1
• B. A - 2, B - 3, C - 4, D - 1
• C. A - 1, B - 2, C - 3, D - 4
• D. A - 3, B - 2, C - 4, D - 1

Answer 1

Answer: (A)

A - 4, B - 3, C - 2, D - 1

$1.008$ g of hydrogen corresponds to $0.5$ mole of $H_2$ which is equal to $3.0115\times {10}^{23}$ molecules.

$245$ g of $KCl{O}_3$ corresponds to $\frac{245}{122.5}=2$ moles. This is equal to $12.046\times {10}^{23}$ molecules.

$71$ g of $C{l}_2$ is equal to $\frac{71}{71}=1$ mole. It occupies $22.4$ L volume at STP.

The atomic mass of silver is $108$ g/atom. $10.8$ g of silver corresponds to $\frac{10.8}{108}=0.1$ gram atom.

Hence, the correct option is A.