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Byju's Answer
Standard VII
Mathematics
Solving Inequalities by Multiplication and Division by a Positive Number
Match the fol...
Question
Match the following algebraic equation with it's solution.
A
5
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B
30
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C
2
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D
16
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Solution
Let's look at the equations one by one and solve them:
A.
3
x
+
5
=
20
⇒
3
x
=
20
−
5
=
15
⇒
3
x
=
15
⇒
x
=
15
3
=
5
B.
x
2
+
10
=
25
⇒
x
2
=
25
−
10
=
15
⇒
x
2
=
15
⇒
x
=
2
×
15
=
30
C.
9
a
+
a
2
=
19
We can add the terms "
9
a
" and "
a
2
" as the unknown are the same.
⇒
9
a
+
a
2
=
9
a
×
2
+
a
2
=
19
⇒
19
a
2
=
19
Cancelling
19
from both sides:
a
2
=
19
19
=
1
a
2
=
1
a
=
2
D.
z
+
5
3
+
1
=
8
⇒
z
+
5
3
=
8
−
1
=
7
⇒
z
+
5
3
=
7
⇒
z
+
5
=
7
×
3
=
21
⇒
z
+
5
=
21
⇒
z
=
16
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