Question

Match the following alkyl radicals with their correct chemical formula:

$\begin{array}{cc}\text{Radical Formula}& \text{Radical Name}\\ \text{(i)}{\text{CH}}_3& \text{(a)}\text{Methyl Radical}\\ \text{(ii)}{\text{CH}}_3{\text{CH}}_2{\text{CH}}_2{\text{CH}}_2& \text{(b)}\text{Ethyl Radical}\\ \text{(iii)}{\text{CH}}_3{\text{CH}}_2& \text{(c)}\text{Propyl Radical}\\ \text{(iv)}{\text{CH}}_3{\text{CH}}_2{\text{CH}}_2& \text{(d)}\text{Butyl Radical}\end{array}$

• A. (a)- (ii), (b)- (i), (c)- (iv), (d)- (iii)
• B. (a)- (i), (b)- (iii), (c)- (iv), (d)- (ii)
• C. (a)- (iv), (b)- (iii), (c)- (ii), (d)- (i)
• D. (a)- (ii), (b)- (iii), (c)- (i), (d)- (iv)

Answer 1

The correct option is B

(a)- (i), (b)- (iii), (c)- (iv), (d)- (ii)

A hydrocarbon becomes a reactive group when a hydrogen atom is replaced from it. This reactive group is known as radicals. Radicals are represented by 'R'. The table given below shows the list of the radicals with their respective names:
$\begin{array}{cc}\text{Radical Formula}& \text{Radical Name}\\ {\text{CH}}_3& \text{Methyl Radical}\\ {\text{CH}}_3{\text{CH}}_2& \text{Ethyl Radical}\\ {\text{CH}}_3{\text{CH}}_2{\text{CH}}_2& \text{Propyl Radical}\\ {\text{CH}}_3{\text{CH}}_2{\text{CH}}_2{\text{CH}}_2& \text{Butyl Radical}\end{array}$

Therefore, the correct match is: (a)- (i), (b)- (iii), (c)- (iv), (d)- (ii)