Match the following and identify the correct option.

(a) $C O (g) + H_{2} (g)$ (i) Permanent hardness of water

(b) $C a S O_{4} + M g S O_{4}$ (ii) An electron deficient hydride

(c) $B_{2} H_{6}$ (iii) Synthesis gas

(d) $H_{2} O_{2}$ (iv) Perhydrol

a-iii, b-ii, c-i, d-iv

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a-iii, b-iv, c-ii, d-i

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a-i, b-iii, c-ii, d-iv

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a-iii, b-i, c-ii, d-iv

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Solution

The correct option is D a-iii, b-i, c-ii, d-iv
• $C O + H_{2}$ : synthesis gas

• $B_{2} H_{6}$ : An electron deficient hydride

• $H_{2} O_{2}$ is sold in market as an antiseptic as Perhydrol.

• Permanent hardness of water is due to the soluble salt of calcium and magnesium in the form of chlorides and sulphates.

Suggest Corrections

Similar questions

(a) $C O (g) + H_{2} (g)$	(i) $M g {(H C O_{3})}_{2} + C a {(H C O_{3})}_{2}$
(b) Temporary hardness of water	(ii) An electron deficient hydride
(c) $B_{2} H_{6}$	(iii) Synthesis gas
(d) $H_{2} O_{2}$	(iv) Non - planar structure

(a)	$C O (g) + H_{2} (g)$	(i)	$M g (H C O_{3}) + C a (H C O_{3})_{2}$
(b)	$Temporary hardness of water$	(ii)	$An electron deficient hydride$
(c)	$B_{2} H_{6}$	(iii)	$Synthesis gas$
(d)	$H_{2} O_{2}$	(iv)	$Non-planar structure$

\begin{matrix} (a) & C O (g) + N_{2} (g) & (i) & An electron precise hydride (b) & Permanent hardness of water & (ii) & Producer gas (c) & C H_{4} & (iii) & Peroxide linkage (d) & H_{2} O_{2} & (iv) & M g C l_{2} + M g S O_{4} \end{matrix}

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(a)	$C O (g) + H_{2} (g)$	(i)	Permanent hardness of water
(b)	$C a S O_{4} + M g S O_{4}$	(ii)	An electron deficient hydride
(c)	$B_{2} H_{6}$	(iii)	Synthesis gas
(d)	$H_{2} O_{2}$	(iv)	Perhydrol