Match the following and identify the correct option.

(a) $C O (g) + H_{2} (g)$ (i) $M g (H C O_{3}) + C a (H C O_{3})_{2}$

(b) $Temporary hardness of water$ (ii) $An electron deficient hydride$

(c) $B_{2} H_{6}$ (iii) $Synthesis gas$

(d) $H_{2} O_{2}$ (iv) $Non-planar structure$

(iii) (iv) (ii) (i)

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(i) (iii) (ii) (iv)

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(iii) (i) (ii) (iv)

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(iii) (ii) (i) (iv)

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Solution

The correct option is C (iii) (i) (ii) (iv)
$\Rightarrow C O (g) + H_{2} (g) = Water gas or synthesis gas$
$\Rightarrow Temporary hardness of water is due to bicarbonates of C a^{2 +} & M g^{2 +}$
$\Rightarrow B_{2} H_{6} is a electron deficient compound due to presence of banana bond.$
$\Rightarrow H_{2} O_{2} open book like structure which is non-planar$

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Similar questions

(a)	$C O (g) + H_{2} (g)$	(i)	$M g (H C O_{3}) + C a (H C O_{3})_{2}$
(b)	$Temporary hardness of water$	(ii)	$An electron deficient hydride$
(c)	$B_{2} H_{6}$	(iii)	$Synthesis gas$
(d)	$H_{2} O_{2}$	(iv)	$Non-planar structure$

(a)	$C O (g) + H_{2} (g)$	(i)	Permanent hardness of water
(b)	$C a S O_{4} + M g S O_{4}$	(ii)	An electron deficient hydride
(c)	$B_{2} H_{6}$	(iii)	Synthesis gas
(d)	$H_{2} O_{2}$	(iv)	Perhydrol

(a) $C O (g) + H_{2} (g)$	(i) $M g {(H C O_{3})}_{2} + C a {(H C O_{3})}_{2}$
(b) Temporary hardness of water	(ii) An electron deficient hydride
(c) $B_{2} H_{6}$	(iii) Synthesis gas
(d) $H_{2} O_{2}$	(iv) Non - planar structure

H_{2} (g) + M_{m} O_{o} (s) (i i)

(i) C O (g) + H_{2} O (g) ⇌ C O_{2} (g) + H_{2} (g); K_{1} (i i) C H_{4} (g) + H_{2} O (g) ⇌ C O (g) + 3 H_{2} (g); K_{2} (i i i) C H_{4} (g) + 2 H_{2} O (g) ⇌ C O_{2} (g) + 4 H_{2} (g); K_{3}

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