Match the following and identify the correct option.

(a) $C O (g) + N_{2} (g)$ (i) $M g C l_{2} + C a S O_{4}$

(b) Permanent hardness of water (ii) An electron precise hydride

(c) $C H_{4}$ (iii) Producer gas

(d) $B_{2} H_{6}$ (iv) Lewis acid

a-iii, b-iv, c-i, d-ii

No worries! We‘ve got your back. Try BYJU‘S free classes today!

a-iii, b-iv, c-ii, d-i

No worries! We‘ve got your back. Try BYJU‘S free classes today!

a-iii, b-i, c-ii, d-iv

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

a-i, b-iii, c-ii, d-iv

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C a-iii, b-i, c-ii, d-iv

Mixture of $C O$ and $N_{2}$ gas is known as producer gas.

Permanent hardness of water is due to presence of $C l^{-}$ and $S O_{4}^{2 -}$ of $C a^{2 +}$ and $M g^{2 +} .$

$C H_{4}$ is an electron precise hydride.

$B_{2} H_{6}$ behaves as a Lewis acid as it is electron deficient.

Suggest Corrections

(a) $C O (g) + H_{2} (g)$	(i) $M g {(H C O_{3})}_{2} + C a {(H C O_{3})}_{2}$
(b) Temporary hardness of water	(ii) An electron deficient hydride
(c) $B_{2} H_{6}$	(iii) Synthesis gas
(d) $H_{2} O_{2}$	(iv) Non - planar structure

(a)	$C O (g) + H_{2} (g)$	(i)	Permanent hardness of water
(b)	$C a S O_{4} + M g S O_{4}$	(ii)	An electron deficient hydride
(c)	$B_{2} H_{6}$	(iii)	Synthesis gas
(d)	$H_{2} O_{2}$	(iv)	Perhydrol

(a)	$C O (g) + H_{2} (g)$	(i)	$M g (H C O_{3}) + C a (H C O_{3})_{2}$
(b)	$Temporary hardness of water$	(ii)	$An electron deficient hydride$
(c)	$B_{2} H_{6}$	(iii)	$Synthesis gas$
(d)	$H_{2} O_{2}$	(iv)	$Non-planar structure$