Question

Match the following and identify the correct option.
$\begin{array}{cccc}\text{(a)}& CO\text{(g)}+N_2\text{(g)}& \text{(i)}& \text{An electron precise hydride}\\ \text{(b)}& \text{Permanent hardness of water}& \text{(ii)}& \text{Producer gas}\\ \text{(c)}& C{H}_4& \text{(iii)}& \text{Peroxide linkage}\\ \text{(d)}& H_2{O}_2& \text{(iv)}& MgC{l}_2+MgS{O}_4\end{array}$

• A. (a) - (i); (b) - (iv); (c) - (ii); (d) - (iii)
• B. (a) - (ii); (b) - (iv); (c) - (i); (d) - (iii)
• C. (a) - (iii); (b) - (ii); (c) - (iv); (d) - (i)
• D. (a) - (ii); (b) - (i); (c) - (iv); (d) - (iii)

Answer 1

The correct option is B (a) - (ii); (b) - (iv); (c) - (i); (d) - (iii)

(i) Chlorides and sulphates of magnesium and calcium causes permanent hardness of water.
(ii)

(iii) $CO+N_2$ is producer gas
(iv) $C{H}_4$ is an electron precise molecular hydride