Match the followingWline- Basic Radical - - Identification-confirmation test during systematic Analysis- Whinea - Fe -3- p - Blue precipitate with- Fe CN - 6- aq 1Wlineb - Pb -2- r - Blood red colouration with KSCN - aq Whinec - Ba -2- r - Black - precipitate with H 2- S gas in the presence of - dil - HCI Whined - Cu -2- s - Yellow - precipitate with - K - 2 CrO -4 aq WlineWine array A- a - pq - b - rs - c - s - d - rtB- a - r- b - pq- c - p- d - s C- a-p- b-s- c-s q- d-r tD- a - rs- b - pq- c - rt- d - s

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Byju's Answer

Standard XII

Chemistry

Valency and Oxidation State

Match the fol...

Question

Match the following
$\begin{matrix} B a s i c R a d i c a l & I d e n t i f i c a t i o n / c o n f i r m a t i o n t e s t d u r i n g s y s t e m a t i c A n a l y s i s (a) & F e^{3 +} & (p) & B l u e p r e c i p i t a t e w i t h K_{4} [F e (C N)_{6}]_{a q} (b) & P b^{2 +} & (r) & B l o o d r e d c o l o u r a t i o n w i t h K S C N_{a q} (c) & B a^{2 +} & (r) & B l a c k p r e c i p i t a t e w i t h H_{2} S g a s i n t h e p r e s e n c e o f d i l H C I (d) & C u^{2 +} & (s) & Y e l l o w p r e c i p i t a t e w i t h K_{2} C r O_{4 a q} (t) & C h o c o l a t e b r o w n p r e c i p i t a t e w i t h K_{4} [F e (C N)_{6}]_{a q} \end{matrix}$

a - p, b - s, c - sq, d - rt

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a - rs, b - pq, c - rt, d - s

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a - pq, b - rs, c - s, d - rt

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a - r, b - pq, c - p, d - s

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Solution

The correct option is C a - pq, b - rs, c - s, d - rt
$F e_{4} [F e (C N)_{6}]_{3}$ Prussian blue ; $F e (S C N)_{3}$ blood red colouration
PbS black ppt; $P b C r O_{4}$ yellow ppt
$B a C r O_{4} y e l l o w p p t$
CuS black ppt; $C u_{2} [F e (C N)_{6}]$ chocolate brown ppt

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Similar questions

Q. Match the compounds/ions in Column I with their properties/reactions in Column II.

\begin{matrix} C o l u m n I & C o l u m n I I A . C_{6} H_{5} C H O & p . g i v e s p r e c i p i t a t e w i t h 2, 4 - d i n i t r o p h e n y l h y d r a z i n e B . C H_{3} C \equiv C H & q . g i v e s p r e c i p i t a t e w i t h A g N O_{3} C . C N^{-} & r . i s a n u c l e o p h i l e D . I^{-} & s . i s i n v o l v e d i n c y a n o h y d r i n f o r m a t i o n \end{matrix}

Q. Match the conversion in

C o l u m n I

with the type(s) of reaction(s) given in

C o l u m n I I

\begin{matrix} C o l u m n I & C o l u m n I I A . & P b S ⟶ P b O & p . & R o a s t i n g B . & C a C O_{3} ⟶ C a O & q . & C a l c i n a t i o n C . & Z n S ⟶ Z n & r . & C a r b o n r e d u c t i o n D . & C u_{2} S ⟶ C u & s . & S e l f - r e d u c t i o n \end{matrix}

$\begin{matrix} c o l u m n 1 & c o l u m n 2 a & p) x b & q) - x c & r) x^{2} d & s) x^{4} \end{matrix}$

Match the graphs with their corresponding functions.

Match Column I with Column II with reference to types of reaction:

$\begin{matrix} Column I & Column II A. & Ionization reaction & p. & {CH}_{4} + 2 O_{2} \to {CO}_{2} + 2 H_{2} O B. & Dissociation reaction & q. & H_{2} O_{2} \to H_{2} O + O_{2} C. & Decomposition reaction & r. & Mg {Cl}_{2} \to {Mg}^{2 +} + 2 {Cl}^{-} D. & Combustion reaction & s. & {H_{2} O}_{(basic)} + {H_{2} O}_{(acidic)} \to H_{3} O^{+} + {OH}^{-} \end{matrix}$

Q. Match each of the reactions given in

C o l u m n I

with the corresponding product(s) given in

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\begin{matrix} C o l u m n I & C o l u m n I I A . & C u + d i l . H N O_{3} & p . & N O B . & C u + c o n c . H N O_{3} & q . & N O_{2} C . & Z n + d i l . H N O_{3} & r . & N_{2} O D . & Z n + c o n c . H N O_{3} & s . & C u (N O_{3})_{2} t . & Z n (N O_{3})_{2} \end{matrix}

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The correct option is C a - pq, b - rs, c - s, d - rtFe4[Fe(CN)6]3 Prussian blue ; Fe(SCN)3 blood red colouration PbS black ppt; Pb CrO4 yellow ppt BaCrO4 yellow ppt CuS black ppt; Cu2[Fe(CN)6] chocolate brown ppt

The correct option is C a - pq, b - rs, c - s, d - rt
$F e_{4} [F e (C N)_{6}]_{3}$ Prussian blue ; $F e (S C N)_{3}$ blood red colouration
PbS black ppt; $P b C r O_{4}$ yellow ppt
$B a C r O_{4} y e l l o w p p t$
CuS black ppt; $C u_{2} [F e (C N)_{6}]$ chocolate brown ppt