Question

Match the following :

$$\begin{array}{cc}Element/Substance& Atomicity\\ \left(i\right)Hydrogen& \left(A\right)3\\ \left(ii\right)Argon& \left(B\right)6\\ \left(iii\right)Sulphur& \left(C\right)Diatomic\\ \left(iv\right)Carbondioxide& \left(D\right)Monoatomic\\ \left(v\right)AmmoniumChloride& \left(E\right)Polyatomic\end{array}$$

• A. i-B; ii-A; iii-D; iv-E; v-C
• B. i-D; ii-E; iii-C; iv-B; v-A
• C. i-D; ii-B; iii-A; iv-E; v-C
• D. i-C; ii-D; iii-E; iv-A; v-B

Answer 1

The correct option is D i-C; ii-D; iii-E; iv-A; v-B

The atomicity of a molecule is the number of atoms present in it.
Elemental Hydrogen ( $H_2$ ) is diatomic i.e. it has two Hydrogen atoms.
Elemental Sulphur is polyatomic i.e. more than 4 atoms. Sulphur exits as $S_6$, $S_7$, $S_8$, $S_{20}$ etc.molecules but $S_8$ is more common.
Elemental Argon exist as independent atoms. So it is monoatomic. Helium, Neon are also monoatomic.
Carbon dioxide (${CO}_2$) compound has 3 atoms. So its atomicity is 3 or triatomic.
Ammonium Chloride (${NH}_{4}Cl$) compound has 6 atoms. So its atomicity is 6.