CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Match the following
Currentsr.m.s values(1) x0 sin ω t(i) x0(2) x0 sin ω t cos ω t(ii) x02(3) x0 sin ω t+x0 cos ω t(iii) x0(22)

A
1. (i), 2. (ii), 3. (iii)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1. (ii), 2. (iii), 3. (i)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
1. (i), 2. (iii), 3. (ii)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 1. (ii), 2. (iii), 3. (i)
1. rms value x02
2. x0 sin ω t cos ω t=x02 sin 2 ω trms value=x022
3. x0 sin ω t+x0 cos ω trms value=(x02)2+(x02)2=x20=x0

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Some Important Quantities
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon