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Question

Match the following:Column-IColumn -II(a) O22(p)Bond order = 0.5(b) CO(q)Bond order = 3(c)NO+(r)Bond order = 1(d)He+2(s)Paramagnetic(t) Diamagnetic

A
(ar,t)
(bq,t)
(cq,t)
(dp,s)
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B
(aq,t)
(br,t)
(cr,t)
(dp,s)
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C
(ar,s)
(bq,s)
(cr,s)
(dr,t)
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D
(aq,s)
(bp,s)
(cp,t)
(dr,t)
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Solution

The correct option is A (ar,t)
(bq,t)
(cq,t)
(dp,s)
Bond order:
B.O=12(bonding eantibonding e)
Magnetic nature:
Unpaired e Paramagnetic
Paired e Diamagnetic

For O22
total number of electron =18
Molecular configuration:
σ1s2,σ1s2,σ2s2,σ2s2,σ2p2z,
π(2p2x=2p2y),π(2p2x=2p2y)
B.O=12(108)=1
all electrons are paired so nature of O22 is diamagnetic.

For He+2
total number of electrons =3
Molecular configuration:
σ1s2,σ1s1
B.O=12(21)=0.5
Paramagnetic nature.

For CO
total number of electron =14
Molecular configuration:
σ1s2,σ1s2,σ2s2,π(2p2x=2p2y),σ2p2z,σ2s2
B.O=12(104)=3
Diamagnetic in nature.

For NO+
total number of electrons =14
Molecular configuration:
σ1s2,σ1s2,σ2s2,σ2s2,π(2p2x=2p2y),σ2p2z
B.O=12(104)=3
Diamagnetic in nature.

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