Match the Following- begin array - Whine- -Column - -Column IIMlhlinea-CuCl2-Na2S2O3-p-Metal ion acts as an oxidizing agent- Whlineb-AgBr-Na2S2O3-q-Formation of - tetrathionate anionllthlinec-AuCl3-Na2S2O3-r-Dissolves in excess of Na - 2 S - 2 O - 3 - -solution due to complex formationillhlined-BaCl2-Na2S2O3-s-Precipitate formed - does not end array A- a - q - b - s - c - p- q- r - d - pB- a - r - q - b - s - c - p - q - r - d - qC- a - r - b - p - c - p - q - r - d - qD- a - p - q - r - b - r - c - p - q - r - d - s

The correct option is D a → p, q, r; b→ r; c → p, q, r; d → s Cu^2+, Au^3+ can oxidize Na_2 S_2 O_3 to Na_2 S_4 O_6 , which reduce to Cu^+1,Au^+1 Cu^+1,Au^+1 a ...

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Byju's Answer

Standard XII

Chemistry

Carbon Dioxide

Match the Fol...

Question

Match the Following:
$\begin{matrix} C o l u m n I & C o l u m n I I (a) & C u C l_{2} + N a_{2} S_{2} O_{3} & (p) & M e t a l i o n a c t s a s a n o x i d i z i n g a g e n t . (b) & A g B r + N a_{2} S_{2} O_{3} & (q) & F o r m a t i o n o f t e t r a t h i o n a t e a n i o n (c) & A u C l_{3} + N a_{2} S_{2} O_{3} & (r) & D i s s o l v e s i n e x c e s s o f N a_{2} S_{2} O_{3} s o l u t i o n d u e t o c o m p l e x f o r m a t i o n (d) & B a C l_{2} + N a_{2} S_{2} O_{3} & (s) & P r e c i p i t a t e f o r m e d d o e s n o t d i s s o l v e i n e x c e s s o f N a_{2} S_{2} O_{3} \end{matrix}$

\to

p, q, r; b

\to

r; c

\to

p, q, r; d

\to

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\to

q; b

\to

s; c

\to

p, q, r; d

\to

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\to

r, q; b

\to

s; c

\to

p, q, r; d

\to

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\to

r; b

\to

p; c

\to

p, q, r; d

\to

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Solution

The correct option is A a $\to$ p, q, r; b $\to$ r; c $\to$ p, q, r; d $\to$ s
$C u^{2 +}, A u^{3 +}$ can oxidize $N a_{2} S_{2} O_{3} t o N a_{2} S_{4} O_{6}$ , which reduce to $C u^{+ 1}, A u^{+ 1}$
$C u^{+ 1}, A u^{+ 1}$ and AgBr form complexes with excess $N a_{2} S_{2} O_{3}$ .
$B a S_{2} O_{3}$ is insoluble in excess of $N a_{2} S_{2} O_{3} .$

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The correct option is A a → p, q, r; b→ r; c → p, q, r; d → s Cu2+,Au3+ can oxidize Na2S2O3toNa2S4O6 , which reduce to Cu+1,Au+1 Cu+1,Au+1 and AgBr form complexes with excess Na2S2O3. BaS2O3 is insoluble in excess of Na2S2O3.