wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Match the following
(a)Bohr effect(i)Increase in O2 causes release of CO2 from Hb into lungs(b)Haldane effect(ii)Increase in CO2 causes release of O2 from Hb into tissues(c)Diffusion(iii)Movement of solvent through semi permeable membrane to the region of higher solute concentration.(d)Osmosis(iv)Movement of solute from high concentration to low concentration

A
a-i, b-ii, c-iii, d-iv
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
a-ii, b-i, c-iv, d-iii
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
a-iii, b-ii, c-i, d-iv
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
a-iv, b-i, c-iii, d-ii
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B a-ii, b-i, c-iv, d-iii
Gases such as oxygen and carbon dioxide are transported within the body via plasma and RBC. Whenever oxygen binds to haemoglobin present in the RBC, the affinity of haemoglobin for carbon dioxide is reduced. The increase in oxygen level within the lungs causes release of carbon dioxide from the RBCs. This reduction of the affinity of haemoglobin for carbon dioxide in lungs is known as Haldane effect.

Whereas, Bohr’s effect states that oxygen binding affinity of haemoglobin is inversely proportional to acidity and concentration of CO2.

Diffusion is the process of the movement of ions or molecules from a region of its higher concentration to a region of lower concentration.

Osmosis is the process in which solvent travels from the region of low solute concentration to the region of higher solute concentration.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon