Question

Match the following
$\begin{array}{cccc}\text{(a)}& \text{Bohr effect}& \text{(i)}& \text{Increase in}{O}_2\text{causes release of}C{O}_2\text{from Hb into lungs}\\ \text{(b)}& \text{Haldane effect}& \text{(ii)}& \text{Increase in}C{O}_2\text{causes release of}{O}_2\text{from Hb into tissues}\\ \text{(c)}& \text{Diffusion}& \text{(iii)}& \text{Movement of solvent through semi permeable membrane to the region of higher solute concentration.}\\ \text{(d)}& \text{Osmosis}& \text{(iv)}& \text{Movement of solute from high concentration to low concentration}\end{array}$

• A. a-i, b-ii, c-iii, d-iv
• B. a-ii, b-i, c-iv, d-iii
• C. a-iii, b-ii, c-i, d-iv
• D. a-iv, b-i, c-iii, d-ii

Answer 1

The correct option is B a-ii, b-i, c-iv, d-iii

Gases such as oxygen and carbon dioxide are transported within the body via plasma and RBC. Whenever oxygen binds to haemoglobin present in the RBC, the affinity of haemoglobin for carbon dioxide is reduced. The increase in oxygen level within the lungs causes release of carbon dioxide from the RBCs. This reduction of the affinity of haemoglobin for carbon dioxide in lungs is known as Haldane effect.

Whereas, Bohr’s effect states that oxygen binding affinity of haemoglobin is inversely proportional to acidity and concentration of $C{O}_2$.

Diffusion is the process of the movement of ions or molecules from a region of its higher concentration to a region of lower concentration.

Osmosis is the process in which solvent travels from the region of low solute concentration to the region of higher solute concentration.