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Question

Match the following columns:
Column I Column II
(a) The polynomial whose zeros
are 2 and −3 is ......... .
(p) x2 − 4x + 1
(b) The polynomial whose zeros are 2+3 and 2-3 is ......... . (q) x2-23x+2
(c) The polynomial whose zeros
are 32 and -12 is ......... .
(r) x2 + x − 6
(d) The polynomial whose zeros
are 3+1 and 3-1
(s) 4x2 − 4x − 3

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Solution

(a) α=2 and β=-3α+β=2+(-3)=-1αβ=2×(-3)=-6 The required polynomial will be x2-(α+β)+αβ=x2+x6.(b) α=2+3 and β=2-3α+β=2+3 +2-3=4αβ=(2+3)(2-3)=4-3=1 The required polynomial will be x2-(α+β)+αβ= x24x+1.(c) α=32 and β=-12α+β=3212=1αβ=34Required polynomial = x2-(α+β)+αβ= x2x34, i.e., 4x24x3(d) α=3+1 and β=3-1α+β=23αβ=3-1=2The required polynomial is x2-(α+β)+α= x223x+2.Thus, the correct matches are (a)-(r),(b)-(p),(c)-(s) and (d)-(q).

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