Match the following cubes of given side with the number of cubes formed by cutting a cube of volume 512 m³

512

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Solution

The volume of a cube = (side) $^{3}$ .
Given, the volume of the bigger cube = 512 m $^{3}$ .
The number of cubes of side length 1 m formed by cutting the cuboid = $\frac{512 m^{3}}{1^{3} m^{3}}$ = 512.
The number of cubes of side length 2 m formed by cutting the cuboid = $\frac{512 m^{3}}{2^{3} m^{3}}$ = 64.
The number of cubes of side length 4 m formed by cutting the cuboid = $\frac{512 m^{3}}{4^{3} m^{3}}$ = 8.
The number of cubes of side length 8 m formed by cutting the cuboid = $\frac{512 m^{3}}{8^{3} m^{3}}$ = 1.

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Match the following cubes of given side with the number of cubes formed by cutting a cube of volume 512 m3

Match the following cubes of given side with the number of cubes formed by cutting a cube of volume 512 m³