Start solving each expressions one by one
a) log0.110.0121
log0.110.0121=log0.110.112
⇒log0.110.0121=2(log0.110.11) [∵logam=mloga]
⇒log0.110.0121=2(1) [∵logaa=1]
⇒log0.110.0121=2
b) log3√25832
log3√25832=log3√2(36.23)
⇒log3√25832=log3√2(3√2)6
⇒log3√25832=6(log3√2(3√2)) [∵logam=mloga]
⇒log3√25832=6(1) [∵logaa=1]
⇒log3√25832=6
c) 2log35−5log32
=2log35−2log35 [∵alogcb=blogca]
⇒2log35−5log32=0