For the figure 1:
∠1, ∠2 and ∠3 forms a linear pair, therefore ∠1 + ∠2 + ∠3 = 180∘
For the figure 2:
∠1, ∠BOC and ∠COE forms a linear pair,
therefore ∠1 +∠BOC +∠COE = 180∘
Given : ∠BOC = 30∘,∠COE = 90∘
⇒ ∠1 +∠BOC +∠COE = 180∘
⇒ ∠1 + 30∘ + 90∘ = 180∘
⇒ ∠1 = 60∘
For the figure 3:
∠4, ∠5 and ∠FOB forms a linear pair,
therefore ∠1 +∠5 +∠FOB = 180∘
Given: ∠FOB = 60∘
⇒ ∠4 + ∠5 + 60∘ = 180∘
⇒ ∠4 + ∠5 = 120∘