From ideal gas equation
pV=nRT
pVnT= constant
At constant
n and
T ,
pV= constant
(X)→(ii),
If we plot a graph between
p and
V, on decreasing the pressure, volume will increase. This is because according to Boyle’s law,
p and
V are inversely related.
pV= constant ( For, constant
n and
T) So, the plot of
p vs
V should be hyperbola.
Hence, option
(A) is the correct match for option
(ii).
(Y)→(iii),
If we plot a graph between
p vs.
1V , we will get a straight line. This is because according to Boyle’s law, pressure is inversely proportional to the volume. But in this case, the value of the volume is
1V
Therefore,
p∝1V
V′=1V , puts this value in the above equation.
p=1×V′
p∝V′
Since,
p is directly proportional to
1V ,
thus, on increasing the value of
p, the value of
1V will also increase and plot will be a straight line.
Hence, option
(B) is the correct match for option
(iii).
(Z)→(i),
If we plot a graph
pV vs.
V, in this case,
pV is constant (at constant temperature and for constant
n). Hence, the value of
pV will be constant irrespective of the value of
V. So, the plot will be a horizontal straight line.
Hence, option
(C) is the correct match for option
(i).
The correct matches can be represented as:
Graphsx and y co-ordinates(A)Xi)p vs. V(B)Yii)p vs. 1V(C)Ziii)pV vs. V