Match the following. I.∫ex(sinx+cosx)dx= a)extanx+c II.∫ex(cosx−sinx)dx= b)exlogsecx+c III.∫ex(tanx+sec2x)dx= c)exsinx+c IV. ∫ex(tanx+logsecx)dx= d)excosx+c
A
I-a, II- b, III- c, IV- d
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B
I-b, II- c, III- a, IV- d
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C
I-c, II- d, III- a, IV- b
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D
I-b, II- d, III- c, IV- a
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Solution
The correct option is C I-c, II- d, III- a, IV- b I.∫ex(sinx+cosx)dx=exsinx+c
II.∫ex(cosx−sinx)dx=excosx+c
III.∫ex(tanx+sec2x)dx=extanx+c
IV.∫ex(log(secx)+tanx)da=exlog(secx)+c
As they are in the form of ∫ex(f(x)+f1(x))dx which is =exf(x)+c