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Question


Match the following
I: lf x2+y26x8y+12=0, a)2
x2+y24x+6y+k=0
cut orthogonally then k=
II lf x2+y22x+3y+k=0, b)10
x2+y2+8x6y7=0
cut orthogonally then k=
III: lf x2+y2+2x2y+4=0, c)24
x2+y2+4x2y+k=0
cut orthogonally then k=

A
a,b,c
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B
b,c,a
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C
c,b,a
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D
a,c,b
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Solution

The correct option is A c,b,a
I. x2+y26x8y+12=0 and x2+y24x+6y+k=0
4(3,4)radius r1=13
If this given circles cuts orthogonally then
2g1g2+2f1f2=c1+c2
So, 20(3)(2)+2(6)(3)=12+k
1224=12+k
k=24
II. x2+y22x+3y+k=0 and x2+y2+8x6y7=0 cuts each othor othogonally than
2g1g2+2f1f2=c1+c2
So, 2x(1)(4)+2(1/2)(3)=k7
89=k7
k=10
III x2+y2+2x2y+4=0 and x2+y2+4x2y+2=0 are orthogonal to each other , so
2x(1)(2)+2x(1)(1)=4+2
6=6
True

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