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Conventional current

Match the fol...

Question

Match the following in the context of electricity:

$i .$ Electron $a .$ Good conductor

$ii .$ Lightning rod $b .$ Losing electric charge

$iii .$ Copper $c .$ Negative charge

$iv .$ Electric discharge $d .$ Protects buildings

i . \to b .

ii . \to a .

iii . \to c .

iv . \to d .

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i . \to c .

ii . \to d .

iii . \to a .

iv . \to b .

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i . \to a .

ii . \to b .

iii . \to c .

iv . \to d .

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i . \to a .

ii . \to d .

iii . \to b .

iv . \to c .

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Solution

The correct option is B $i . \to c .$
$ii . \to d .$
$iii . \to a .$
$iv . \to b .$
Electrons are negatively charged particles.
A lightning rod protects buildings from large currents caused in lightning.
Copper is an excellent conductor of electricity.
Electric discharge is a process in which a charged object loses it charge by giving it away to another object.
So, the correct matches are as follows:

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Similar questions

Column- $I$	Column- $II$
$(i) .$ Positively charged Spherical conductor.	$(a) .$ At the surface , electric field is continuous and maximum.
$(ii) .$ Spherical non conductor having uniform volume charge distribution.	$(b) .$ at the surface, electric field is dis-continuous.
$(iii) .$ Positively charged ring.	$(c) .$ Electric field is uniform.
$(iv) .$ Infinite thin sheet of positive charge	$(d) .$ at the center, electric field is zero.

Column- $I$	Column- $II$
$(i) .$ Infinite sheet of charge having positive charges.	$(a) .$ Uniform non-zero electric field intensity in the vicinity.
$(ii) .$ At the center of Non-conducting uniformly charged solid sphere.	$(b) .$ Uniform decreasing potential in the vicinity.
$(iii) .$ Inside a positively charged conducting sphere taking infinity as a reference point.	$(c) .$ maximum magnitude of potential.

\begin{matrix} Colum A & Colum B (a) Electric power & (i) Volt (a) kWh & (ii) Joule (c) Electirc current & (iii) Volt \times Ampere (d) Eelctric energy & (iv) Watt (e) Watt & (v) Ampere (f) Potential difference & (vi) Electrical energy \end{matrix}

Q

A

B

A

C

A

D

A

E

σ_{1}

σ_{2}

$(A)$ If $σ_{1} + σ_{2} = 0$	$(P)$ Electric field in region $III$ is towards right.
$(B)$ If $σ_{1} + σ_{2} > 0$	$(Q)$ Electric field in region $I$ is zero.
$(C)$ If $σ_{1} + σ_{2} < 0$	$(R)$ Electric field in region $I$ is towards right.
$(S)$ None.
$(T)$ Nothing can be said.

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