Question

Match the following:

List-I	List-II
1. Area bounded by $y^2=4ax$ and $x^2=4ay$ is	a. $\frac{8a^2}{3}$
2. Area bounded by $y^2=4ax$ and its latusrectum is	b. $\frac{a^2}{6}$
3. Area bounded by $x=2cos\theta ,y=2sin\theta$ is	c. $\frac{16a^2}{3}$
4. Area bounded by $\sqrt{x}+\sqrt{y}=\sqrt{a}$ is	d. $2\pi$

The correct match is

• A. c,a,d,b
• B. b,d,a,c
• C. a,b,c,d
• D. c,d,b,a

Answer 1

The correct option is A c,a,d,b

1. $\stackrel{4a}{\underset{0}{\int }}(\sqrt{4ax}-\frac{x^2}{4a})dx$
$=\frac{16a^2}{3}squnits.$
2. $2\stackrel{a}{\underset{0}{\int }}\left(4ax\right)dx$
$=\frac{8a^3}{3}squnits.$
3. $x^2+y^2=4$
$\stackrel{-a}{\underset{-a}{\int }}(\sqrt{(}4-x^2)dx$ $=2\pi$
So, c,a,d,b