Match the following:
List - I List - II
A. Inversion temperature (i) $a / R b$
B. Boyle's temperature (ii) $8 a / 27 R b$
C. Critical temperature (iii) $2 a / R b$

A - (i), B - (i i), C - (i i i)

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A - (i i i), B - (i i), C - (i)

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A - (i i i), B - (i), C - (i i)

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A - (i), B - (i i i), C - (i i)

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Solution

The correct option is C $A - (i i i), B - (i), C - (i i)$
A. Inversion temperature $T_{i} = \frac{2 a}{R b}$
B. Boyle's temperature $T_{B} = \frac{a}{R b}$
Note:
$T_{B} = \frac{a}{b R} = \frac{1}{2 T_{i}}$
C. Critical temperature $T_{c} = \frac{8 a}{27 R b}$

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List - I	List - II
A. Inversion temperature	(i) $a / R b$
B. Boyle's temperature	(ii) $8 a / 27 R b$
C. Critical temperature	(iii) $2 a / R b$

Match the following:List - IList - IIA. Inversion temperature(i) a/RbB. Boyle's temperature(ii) 8a/27RbC. Critical temperature(iii) 2a/Rb

The correct option is C A−(iii),B−(i),C−(ii)A. Inversion temperature Ti=2aRbB. Boyle's temperature TB=aRbNote: TB=abR=12TiC. Critical temperature Tc=8a27Rb

Match the following:
List - I List - II
A. Inversion temperature (i) $a / R b$
B. Boyle's temperature (ii) $8 a / 27 R b$
C. Critical temperature (iii) $2 a / R b$

The correct option is C $A - (i i i), B - (i), C - (i i)$
A. Inversion temperature $T_{i} = \frac{2 a}{R b}$
B. Boyle's temperature $T_{B} = \frac{a}{R b}$
Note:
$T_{B} = \frac{a}{b R} = \frac{1}{2 T_{i}}$
C. Critical temperature $T_{c} = \frac{8 a}{27 R b}$