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Question

Match the following lists :

1) f:RR defind by f(x)=ax+b is (a0)a) injection but not surjection
2) f:RR defind by f(x)=[x] isb) surjection but not injection
3) f:R[0,) defind by f(x)=|x| is c) bijection
4) f:NN defind by f(x)=x3 isd) neither injection nor surjection

A
1c,2d,3a,4b
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B
1c,2d,3b,4a
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C
1d,2c,3b,4a
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D
1d,2c,3a,4b
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Solution

The correct option is B 1c,2d,3b,4a
(I) f(x)=ax+b,a0
f(x) will be increasing or decreasing depending on a.
So it is one-one & onto.
(II) f(x)=[x]
neither one-one nor onto
(III) f(x)x
onto but not one-one
(IV) f(x)=x3
one-one but not onto.

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