Question

Match the following molecules released when the products (in the right column) are formed during glycolysis:

$\begin{array}{cc}\text{i. ATP}& \text{1. Triose bisphosphate}\\ \text{ii. NADH}& \text{2. Phosphoenolpyruvate}\\ \text{iii.}{H}_{2}O& \text{3. Triose phosphate}\end{array}$

• A. i-2, ii-3, iii-1
• B. i-3, ii-1, iii-2
• C. i-1, ii-3, iii-2
• D. i-1, ii-2, iii-3

Answer 1

The correct option is B i-3, ii-1, iii-2

The pathway of the breakdown of glucose into pyruvic acid is termed as glycolysis. This pathway is a step-wise process in which several molecules are released like 4 ATP, 2 ADP, water and 2 (NADH + H${}^{+)}$ when the reactant intermediates undergo a reaction. The steps are given below:


The enzyme glyceraldehyde-3-phosphate dehydrogenase transfers hydrogen molecule from glyceraldehyde-3-phosphate to NAD+ to form NADH + H+ and converts glyceraldehyde-3-phosphate to 1,3-biphosphoglyceric acid (triose biphosphate).


Phosphate is transferred from 1,3-bisphosphoglycerate to ADP to form ATP with the help of phosphoglycerate kinase. 3-phosphoglycerate (triose phosphate) and ATP are obtained at the end of this reaction.

The enzyme enolase removes a water molecule from 2-phosphoglycerate to form phosphoenolpyruvate.