Match the following object positions with their respective image positions.
When the object is kept at 2F1, we get an inverted image which is of same size of the object at 2F2.
⇒Since image height > object height and image is inverted.
⇒So, object must be kept between 2F1 and F1.
⇒Since image height = object height,
⇒So object must be kept at 2F1.
⇒ Since image and object is at same side. So, the only possibility is object kept between focus and optical centre.