Question

Match the following sets of number of unpaired electrons and magnetic moments.

Set -I Set -II

A) Sc${}^{3+}$ 1) 5, 5.92 B.M

B) V${}^{2+}$ 2) 1, 1.73 B.M.

C) Fe${}^{3+}$ 3) 0, 0 B.M.

D) Cu${}^{2+}$ 4) 3, 3.87 B.M

The correct matching for A B C D is:

• A. 3 4 1 2
• B. 4 1 2 3
• C. 3 4 2 1
• D. 2 1 3 4

Answer 1

The correct option is A 3 4 1 2

Option (A) is correct.

A). Number of unpaired electrons and magnetic moment of $S{c}^{3+}$ is 0 and 0 respectively.

Magnetic moment, $\mu =\sqrt{n(n+2)}$

$=\sqrt{0(0+2)}$

$=0$

B). Number of unpaired electrons and magnetic moment of $V^{2+}$ is 3 and 3.87 respectively.

Magnetic moment, $\mu =\sqrt{n(n+2)}$

$=\sqrt{3(3+2)}$

$=3.87BM$

C). Number of unpaired electrons and magnetic moment of $F{e}^{3+}$ is 5 and 5.92 respectively.

Magnetic moment, $\mu =\sqrt{5(5+2)}=5.92BM$

D). Number of unpaired electrons and magnetic moment of $C{u}^{2+}$ is 1 and 1.73 respectively.

Magnetic moment, $\mu =\sqrt{1(1+2)}=1.73BM$