Match the following solid objects with the expressions of their volume.
A
πr2h−13πr2h
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B
πr2h+23πr3
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C
2πr12h1+πr22h2
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Solution
Volume of this solid object = Volume of the cylinder - volume of the cone = πr2h−13πr2h ∴ Volume of this solid object = πr2h−13πr2h
Volume of this solid object = Volume of the cylinder + Volume of hemisphere = πr2h+23πr3 ∴ Volume of this solid object = πr2h+23πr3
Volume of this solid object = Volume of two cylinders with radii r1 + Volume of cylinder with radius r2 = 2×πr12h1+πr22h2 = 2πr12h1+πr22h2 ∴ Volume of this solid object = 2πr12h1+πr22h2