Question

Match the following table:

$\begin{array}{cc}\text{Theorem Statement}& \text{Theorem Name}\\ \text{(a) The line segment joining the mid-points of}& \text{(i) Basics proportionality theorem}\\ \text{two sides of a triangle is parallel to the third side}& \\ \text{(b) A line parallel to one side of a triangle divides}& \text{(ii) Mid point theorem}\\ \text{the other two sides into parts of equal}& \\ \text{poportion}& \\ \text{(c) If a line divides the any tw o sides of a triangle}& \text{(iii) Converse of Basic porpotionality theorem}\\ \text{in the same ratio, then the line must be parallel}& \\ \text{to the third side.}& \end{array}$

• A. (i) - b; (ii) - a; (iii) - c; (iv) - d
• B. (i) - a; (ii) - b; (iii) - c; (iv) - d
• C. (i) - b; (ii) - c; (iii) - a; (iv) - d
• D. (i) - d; (ii) - a; (iii) - c; (iv) - b

Answer 1

The correct option is A

(i) - b; (ii) - a; (iii) - c; (iv) - d

Mid point theorem - The line segment joining the mid-points of two sides of a triangle is parallel to the third side.

Converse of mid point theorem - The line drawn through the mid-point of one side of a triangle, parallel to another side, bisects the third side.

Basic proportionality theorem - A line parallel to one side of a triangle divides the other two sides into parts of equal proportion.

Converse of basic proportionality theorem - If a line divides the any two sides of a triangle in the same ratio, then, the line must be parallel to the third side.