Question

Match the following to solve each pattern.

• A. 20N
• B. 48
• C. 140

Answer 1

Case 1:
The sequence can be split separately as alphabets and numbers.
10,11,13,16,
If we add 1 to the sequence we get 2nd term and we add 2 to the 2nd term we get 3rd term and so on. It can be shown as
10 + 1 = 11
11+ 2 = 13
13 + 3 = 16

and next term will be 16 + 4 = 20

For alphabets, the sequence is every alternate alphabet.
First alphabet taken is F, the next is H and so on.
So, for the given last term, 16L the next alternate alphabet after L is N
Hence, the next term in the sequence is 20N

Case 2:
In this sequence, the difference between two consecutive terms is 11. Hence subtracting 11 from the last term, 59, we get 48.

Case 3:
Each consecutive term in the given sequence is obtained by adding 15 to the previous term. Hence, adding 15 to the last given term, 125, we get 140.
125 + 15 = 140