Match the following trapeziums to their correct areas.

200

m^{2}

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m^{2}

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150

m^{2}

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Solution

Area of trapezium JAIL = $\frac{1}{2}$ h (a+b)

= $\frac{1}{2} \times 20 \times (8 + 12)$

= $\frac{1}{2} \times 20 \times 20$

=200 $m^{2}$

Area of trapezium MAIL = $\frac{1}{2}$ h (a+b)

= $\frac{1}{2} \times 11 \times (8 + 4)$

= $\frac{1}{2} \times 11 \times 12$

=66 $m^{2}$

Area of trapezium RAIL = $\frac{1}{2}$ h (a+b)

= $\frac{1}{2} \times 10 \times (10 + 20)$

= $\frac{1}{2} \times 10 \times 30$

=150 $m^{2}$

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Match the following trapeziums to their correct areas.

Area of trapezium JAIL = 12 h (a+b) = 12×20×(8+12) = 12×20×20 =200 m2 Area of trapezium MAIL = 12 h (a+b) = 12×11×(8+4) = 12×11×12 =66 m2 Area of trapezium RAIL = 12 h (a+b) = 12×10×(10+20) = 12×10×30 =150 m2